Show that Sec2 x-tan 6 x-1-3 2 x tan 2 x

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Differentiation Using Substitution

Show that Sec...

Question

Show that Sec²x - tan⁶x= 1 +3sec²x tan²x

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Prove that

sin⁶x .- tan⁶ x - 3 sec²x •

tan²x = 1

s e c^{6} x - \tan^{6} x = 1 + 3 s e c^{2} x \tan^{2} x

{sec}^{6} x - {tan}^{6} x = 1 + 3 {sec}^{2} x \times {tan}^{2} x

{sec}^{6} x - {tan}^{6} x = 1 + 3 {sec}^{2} x \times {tan}^{2} x = 1

\frac{(sin 7 x + sin 5 x) + (sin 9 x + sin 3 x)}{(cos 7 x + cos 5 x) + (cos 9 x + cos 3 x)} = tan 6 x

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