Show that stereocentres present in the following compound.
$H_{3} C - C H = C H - C H | B r - C H | C l - C H_{3}$ .

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Solution

Refer to Image)
$1, 2$ for Optical isomerism.
$3, 4$ for Geometrical isomerism.

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Similar questions

H_{3} C - C H = C | - C H_{3} C | B r H - C H_{3}

H_{3} C - C = C H - C H - C H_{3}

∣

∣

C l

C H_{3}

C H_{3} - C | H C l - C | H B r - C | H O H - C H_{3}

H_{3} C - C H_{2} - C H_{3} | C = C H - C | H C_{2} H_{5} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{3}

{C H}_{3} - C O - C H | C l - C H | B r - C O O H

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