Show that -tan 2 A -tan 2 B -sin 2 A -sin 2 B - cos 2 A -cos 2 B

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Range of Trigonometric Ratios from 0 to 90 Degrees

Show that :ta...

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Show that :
tan²A-tan²B=sin²A-sin²B/cos²A.cos²B

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$t a n^{2} A - t a n^{2} B = \frac{s i n^{2} A - s i n^{2} B}{c o s^{2} A . c o s^{2} B}$

t a n^{2} a - t a n^{2} b = \frac{s i n^{2} a - s i n^{2} b}{c o s^{2} a . c o s^{2} b}

t a n^{2} A - t a n^{2} B = \frac{c o s^{2} B - c o s^{2} A}{c o s^{2} B c o s^{2} A} = \frac{s i n^{2} A - s i n^{2} B}{c o s^{2} A c o s^{2} B}

\frac{(t a n^{2} A - t a n^{2} B = (s i n^{2} A - s i n^{2} B)}{(C o s^{2} A \times C o s^{2} B)}

(i) (s i n^{2} A c o s^{2} B - c o s^{2} A s i n^{2} B) = (s i n^{2} A - s i n^{2} B)

(i i) (t a n^{2} A s e c^{2} B - s e c^{2} A t a n^{2} B) = (t a n^{2} A - t a n^{2} B)

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