CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Show that the area of the triangle contained between the vectors a and b is one half of the magnitude of a × b.

Open in App
Solution

The following figure shows two vectors a and b at an angle θ extended to form a parallelogram.



From the above figure in ΔOMN,

sinθ= MN OM = MN | b | MN=| b |sinθ (1)

The magnitude for cross product of aand b is,

| a×b |=| a || b |sinθ

From the equation (1),

| a×b |=( OK )( MN )

Multiply and divide by 2.

| a×b |=( OK )( MN )× 2 2 =2×AreaofΔOMK AreaofΔOMK= 1 2 | a×b |

Thus, the area of the triangle contained between the vectors a and b is one half the magnitude of the a×b.


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon