Show that the diagonals of the parallelogram whose sides are lx+my+n=0,lx+my+n=0,mx+ly+n=0,mx+ly+n=0 include an angle π/2.
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Solution
The distances between two sets of parallel sides is each n−n′√(l2−m2) i.e. p1=p2 hence the Parallelgram is rhombus whose diagonals we know intersect at right angles.