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Question

Show that the differential equation dydx=y2xyx2 is homogeneous and also solve it.

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Solution

dydx=y2xyx2=f(x,y)f(mx,my)=m2y2m2xym2x2=y2xyx2=f(x,y)
where m0.
Therefore, the differential equation is homogeneous.
v=xyx=vydxdy=ydvdy+vdxdy=xyx2y2=xyx2y2dxdy=vv2=ydvdy+vv2=ydvdydyy=dvv2lny+C=1v=yxy=x(lny+C)

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