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Byju's Answer
Standard XII
Mathematics
Properties of Conjugate of a Complex Number
Show that the...
Question
Show that the equation
a
x
2
+
b
x
+
c
=
0
and
x
2
+
x
+
1
=
0
cannot have a common root unless
a
=
b
=
c
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Solution
Given that,
x
2
+
x
+
1
=
0
has non real roots.
Hence,
a
x
2
+
b
x
+
c
=
0
and above equation has common roots if
a
1
=
b
1
=
c
1
⇒
a
=
b
=
c
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0
Similar questions
Q.
Assertion :
Let
a
,
b
,
c
be real such that
a
x
2
+
b
x
+
c
=
0
and
x
2
+
x
+
1
=
0
have a common root.
a
=
b
=
c
Reason: Two quadratic equations with real coefficients cannot have only one imaginary root common.
Q.
If
a
,
b
,
c
ϵ
R
and equations
a
x
2
+
b
x
+
c
=
0
and
x
2
+
2
x
+
9
=
0
have a common root, show that
a
:
b
:
c
=
1
:
2
:
9.
Q.
Show that the roots of the equations
(
x
−
a
)
(
x
−
b
)
+
(
x
−
b
)
(
x
−
c
)
+
(
x
−
c
)
(
x
−
a
)
=
0
and they cannot be equal unless
a
=
b
=
c
.
Q.
If the equations
a
x
2
+
b
x
+
c
=
0
and
x
2
+
2
x
+
4
=
0
have a common root then find a : b : c.
Q.
If equation
a
x
2
+
b
x
+
c
=
0
and
x
2
+
2
x
+
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=
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have a common root, then if
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:
c
=
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B
+
C
=
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