CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
44
You visited us 44 times! Enjoying our articles? Unlock Full Access!
Question

Show that the equation x2+x+2=0 equation has real roots, and solve by using quadratic formula.

Open in App
Solution

using the quadratic formula:


x=(−b-√(b^2−4ac))/2a
or
x=(−b+√(b^2−4ac))/2a


Here a=1 , b=1 and c=2


So,


x=((−1+√(1−4∗1∗2))/2∗1


or


x=((−1-√(1−4∗1∗2))/2∗1


which is equal to :


x=(−1+√7i)/2
or
x=(−1−√7i)/2

therefore the roots are not real roots
and they are
x=(−1+√7i)/2
or
x=(−1−√7i)/2

flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon