Question

Show that the following points form a right angled triangle.

(10, 0), (18, 0) and (10, 15)

Answer 1

Given,

$A(10,0),B(18,0),C(10,15)$

$AB=\sqrt{8^2}$ ; $BC=\sqrt{8^2+{15}^2}$

$AC=\sqrt{{15}^2}$

$\because A{B}^2+A{C}^2=B{C}^2$

Hence it is Right angled $\Delta$