Show that the following statement is true by the method of contrapositive p : "If x is an integer and x2 is even, then x is also even"
The given compound statement is of the form "if p then q"
p:xϵZ and x2 is even.
q : x is an even integer.
We assume that q is false then x is not an even integer.
⇒ x is an odd integer
⇒x2 is an odd integer.
⇒ p is false
So when q is false, p is false.
Thus the given compound statement is true.