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Question

Show that the four points A, B, C and D with position vectors a, b, c and d respectively are coplanar if and only if 3a - 2b + c - 2d = 0 .

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Solution

Necessary Condition: Firstly , let a, b, c are coplanar vectors. Then, one of them is expressible as a linear combination of the other two. Let c= xa + yb for some scalars x, y. Then,
c = xa + yb for some scalars x, y.
la + mb + nc = 0, where l=x, m=y, n=-1.
Thus, if a, b, c are coplanar vectors, then there exists a scalars l, m, n not all zero simultaneously satisfying la + mb + nc = 0 where l, m, n are not all zero simultaneously.

Sufficient Condition: Let a, b, c are three scalars such that there exists scalars l, m, n not all zero simultaneously satisfying la + mb + nc= 0. We have to prove that a, b, c are coplanar vectors.
Now,
la + mb + nc = 0. nc =-la - mb. c = -lna + -mnb.
c is a linear combination of a and b.
c lies in a plane a and b.
Hence, a, b, c are coplanar vectors.

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