Show that the function given by $f (x) = 3 x + 17$ is strictly increasing on $R$ .

Open in App

Solution

Given, $f (x) = 3 x + 17$
$f^{'} (x) = 3 > 0, \forall x \in R .$
Thus, the given function is strictly increasing on $R$ .

Suggest Corrections

Similar questions

Show that the function given by f(x) = 3x + 17 is strictly increasing on R.

Show that the function given by $f (x) = 3^{2 x}$ is strictly increasing on R.

f (x) = e^{2 x}

R

Show that the function given by f(x) = e²^x is strictly increasing on R.

f

f (x) = x^{3} - 3 x^{2} + 4 x, x \in R

Join BYJU'S Learning Program