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Question

Show that the line given by x(a+2b)+y(a+3b)=a+b for different values of a and b pass through a fixed point.

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Solution

x(a+zb)+y(a+zb)=a+ba(x+y)+b(2x+3y)=a+bx+y=1(i)2x+3y=1(ii)Multiply2ineq.(i)2x+2y=22x+3y=1¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯y=1y=1putyineq(i)x1=1x=2fixedpoint(2,1)

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