Show that the lines x−57=y+2−5=z1 and x1=y2=z3 perpendicular to each other.
The equations of the given lines are x−57=y+2−5=z1 and x1=y2=z3 direction ratios of the given lines are respectively (7, - 5,1) and (1, 2, 3).
Two lines with direction ratios, a1,b1,c1 and a2,b2,c2 are perpendicular to each other, if
a1a2+b1b2+c1c+2=0
∴ (7) (1) + (-5) (2) + (1) (3) = 7 - 10 + 3 = 0
Therefore, the given lines are perpendicular.