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Question

Show that the lines r=2j^-3k^+λi^+2j^+3k^ and r=2i^+6j^+3k^+μ2i^+3j^+4k^ are coplanar. Also, find the equation of the plane containing them.

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Solution

We know that the lines r=a1+λ b1 and r=a2+μ b2 are coplanar if a1. b1×b2 = a2. b1×b2 and the equation of the plane containing them isr. b1×b2 = a1. b1×b2.Here,a1 = 0 i^+2 j^-3 k^; b1 = i^+2 j^+3 k^; a2 = 2 i^+6 j^+3 k^; b2 = 2 i^+3 j^+4 k^b1×b2 = i^j^k^123234 = -i^+2 j^-k^a1. b1×b2 = 0 i^+2 j^-3 k^. -i^+2 j^-k^ = 0 + 4 + 3 = 7a2. b1×b2 = 2 i^ + 6 j^ + 3 k^. -i^ + 2 j ^- k^ = -2 + 12 - 3 = 7Clearly, a1. b1×b2=a2. b1×b2Hence, the given lines are coplanar.The equation of the plane containing the given lines isr. b1×b2 = a1. b1×b2r. -i^+2 j^-k^ = 0 i^ + 2 j^ - 3 k^. -i ^+ 2 j^ - k^r. -i^ + 2 j^ - k^ = 7r. i^ - 2 j^ + k^ + 7 = 0

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