Objective function : Z=−x+2y
We have to minimize and maximize Z on constraints
x≥3
x+y≥5
x+2y≥6
y≥0
After plotting all the constraints on coordinate plane, we get the feasible region as shown in the image.
Corner points | Value of Z=−x+2y |
(3,2) | 1 (Maximum) |
(4,1) | -2 |
(6,0) | -6 (Minimum) |
Now, since region is unbounded. Hence we need to confirm that minimum and maximum value obtained through corner points is true or not.
Now, plot the region Z≤−6⇒−x+2y≤−6. Since, this region has common region with feasible region. Hence, there are many points where value of Z will be less than -6. So, minimum of Z not exists.
(Example :- check the value of Z at (8,0.5) )
Similarly, plot the region Z≥1⇒−x+2y≥1. Since, this region has common region with feasible region. Hence there are many points where value of Z will be greater than 1. So, maximum of Z doesn't exists.
(Example :- check the value of Z at (4,4) )