Show that the middle term in the expansion of $(1 + x)^{n}$ is $6 x^{2}$ if $n = 4$

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Solution

The middle term of expansion when n is even is $^{n} C_{n / 2} x^{n / 2}$
Here $n = 4$
So the term is $^{4} C_{4 / 2} x^{4 / 2} = 6 x^{2}$

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