Show that the minimum energy needed to separate a proton from a nucleus with Z protons and N neutrons is △E=(Mz−1,N+MH−MZ,n)C2 Where MZ,n= mass of an atom with Z protons and N neutrons in the nucleus and MH= mass of a hydrogen atom. This energy is known as proton-separation energy.
Ezn→Ez−1′N+P1
⇒EZN→Ez−1+1H1
{As hydrogen has no neutrons but proton only}
△E=(Mz−1′N+NNH−Mz,N)C2