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Question

Show that the minimum energy needed to separate a proton from a nucleus with Z protons and N neutrons is E=(Mz1,N+MHMZ,n)C2 Where MZ,n= mass of an atom with Z protons and N neutrons in the nucleus and MH= mass of a hydrogen atom. This energy is known as proton-separation energy.

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Solution

EznEz1N+P1

EZNEz1+1H1

{As hydrogen has no neutrons but proton only}

E=(Mz1N+NNHMz,N)C2


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