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Question

show that the number of ways if selecting nobject out of 3nobjects, n of which are like and rest different is 22n1+(2n)!2(n!)2

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show that the number of ways if selecting nn−object out of 3n3n−objects, nn of which are like and rest differnt is 22n1+(2n)!2(n!)2

solution:
Accordingtoques:wehave3nobjectsinwhichselectnobjects,and,objects3nhasnisidenticaland2n,differentobjects.Now,numberofways:n,identicalobjects–––––––––––––––––––––:0,1,2.....3......nand,2n,differentobject–––––––––––––––––––––:n,n1,n2,......n3.......0thentheno.ofwaysandaddingtheno.ofways:2nc0+2nc1+2nc2+.......2nc3+......2ncn[weknowthat:2nc0+2nc1+2nc2+.....2ncn+.....2ncn+1....2nc2n=22n]Again,2ncn+1+2ncn+2......2nc2n,wecanalsowriteas:2nc2n(n+1)+2nc2n(n+2).......2nc2n2n|(ncr=ncnr)2ncn1+2ncn2.......2nc0Againwewrite:2nc0+2nc1+2nc2+.....2ncn1+2ncn+2ncn+1......2nc2n=22nadding2ncnintoR.H.S2nc0+2nc1+2nc2+.....2ncn1+2ncn––––––––––––––––––––––––––––––––––––––+2ncn+1......2nc2n–––––––––––––––––=22n+2ncnsupposewevaluedtheequn:s+s=22n+2ncn2s=22n+2ncn2s=22n+(2n)!n!n!s=22n1+(2n)!2(n!)2(prove)

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