MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Locating a Given Point on a Graph Paper

Show that the...

Question

Show that the point (2a, 4a), (2a, 6a) and (2a + root 3, 5a) are the vertices of an equilateral triangle.

Open in App

Solution

Suggest Corrections

thumbs-up

2

Similar questions

(2 a, 4 a), (2 a, 6 a)

(2 a + \sqrt{3} a, 5 a)

are the vertices of

(2 a, 4 a), (2 a, 6 a)

(2 a + \sqrt{3} a, 5 a)

are the vertices of

Q. Assertion :If A(2a, 4a) and B(2a, 6a) are two vertices of a equilateral triangle ABC then the vertex C is given by

(2 a + a \sqrt{3}, 5 a) .

Reason: In equilateral triangle all the coordinates of three vertices can be rational.

(2 a, 4 a)

(2 a, 6 a)

(2 a + \sqrt{3} a, 5 a)

a > 0

) are vertices of

A (2 a, 4 a)

B (2 a, 6 a)

C (2 a + \sqrt{3} a, 5 a)

a > 0

) are vertices of :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Locating a given point on a graph paper

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Locating a Given Point on a Graph Paper

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon