Show that the point x- y given by x- 2at -1-t2 and y-a1-t2-1-t2 lies on a circle for all real values of that such that -1 - t - 1- where a is any given real numbers-OrFind the equations of the altitudes of the triangle whose vertices are A 7-1- B -2-8 and C 1-2-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Coordinates of a Point in Space

Show that the...

Question

Show that the point (x, y) given by $x = \frac{2 a t}{1 + t^{2}}$ and $y = \frac{a (1 - t^{2})}{1 + t^{2}}$ lies on a circle for all real values of that such that $- 1 \leq t \leq 1$ , where a is any given real numbers.

Or

Find the equations of the altitudes of the triangle whose vertices are A (7, - 1), B(- 2, 8) and C (1, 2).

Open in App

Solution

Suggest Corrections

Similar questions

x = \frac{2 a t}{1 + t^{2}}

y = a (\frac{1 - t^{2}}{1 + t^{2}})

- 1 \leq t \leq 1

x = a (\frac{1 - t^{2}}{1 + t^{2}})

y = \frac{2 a t}{1 + t^{2}}

t

Locus of the point given by the equations $x = \frac{2 a t}{1 + t^{2}}, y = \frac{a (1 - t^{2})}{1 - t^{2}} (- 1 \leq t \leq 1)$ is a

x = a (\frac{1 - t^{2}}{1 + t^{2}})

y = \frac{2 a t}{1 + t^{2}}

t

x = a (\frac{1 - t^{2}}{1 + t^{2}})

y = \frac{2 a t}{1 + t^{2}}

t

Join BYJU'S Learning Program