Show that the positive vector of the point P, which divides the line joining the points A and B having position vectors →a and →b internally in ratio m:n is m→b+n→am+n.
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Solution
Let O be the origin representing the position vectors OA and OB with respect to the two points A and B. Let A and B be divided by a third point P internally in the ratio m:n ∴APAB=mn or nAP=mPB ⇒n→AP=m→PB ⇒n(→OP−→OA)=m(→OB−→OP) ⇒n(→r−→a)=m(→b−→r) n→r−n→a=m→b−m→r ∴m→r+n→r=m→b+n→a or →r=m→b+n→am+n (proved).