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Question

Show that the quadrilateral formed by joining the mid points of the sides of a rhombus taken in order, form a rectangle .

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Solution

Let ABCD be a rhombus and P, Q, R and S be the mid points of sides of AB, BC, CD and DA respectively.
In ΔABD and BDC we have
SP||BD and SP=12BD(1)
RQ||BD and RQ=12BD(2)
from (1) and (2) we get
PQRS is a parallelogram
As diagonals of rhombus bisect each other at right angle
ACBD
Since SP||BD, PQ||AC and ACBD
SPPQ
LQPS:90o (3)
From above results we have parallelogram PQRS is rectangle.

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