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Byju's Answer
Standard VI
Mathematics
Quadrilaterals
Show that the...
Question
Show that the quadrilateral formed by joining the mid points of the sides of a rhombus taken in order, form a rectangle .
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Solution
Let ABCD be a rhombus and P, Q, R and S be the mid points of sides of AB, BC, CD and DA respectively.
In
Δ
ABD and BDC we have
SP
|
|
BD and SP
=
1
2
B
D
→
(
1
)
RQ
|
|
BD and RQ
=
1
2
B
D
→
(
2
)
from
(
1
)
and
(
2
)
we get
PQRS is a parallelogram
As diagonals of rhombus bisect each other at right angle
∴
A
C
⊥
B
D
Since SP
|
|
BD, PQ
|
|
AC and
A
C
⊥
B
D
∴
S
P
⊥
P
Q
LQPS
:
90
o
→
(
3
)
From above results we have parallelogram PQRS is rectangle.
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Similar questions
Q.
Show that the quadrilateral formed by joining the mid-points of the consecutive sides of a rectangle is a rhombus.