wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Show that the quadrilateral formed by joining the mid points of the sides of a rhombus taken in order, form a rectangle .

Open in App
Solution

Let ABCD be a rhombus and P, Q, R and S be the mid points of sides of AB, BC, CD and DA respectively.
In ΔABD and BDC we have
SP||BD and SP=12BD(1)
RQ||BD and RQ=12BD(2)
from (1) and (2) we get
PQRS is a parallelogram
As diagonals of rhombus bisect each other at right angle
ACBD
Since SP||BD, PQ||AC and ACBD
SPPQ
LQPS:90o (3)
From above results we have parallelogram PQRS is rectangle.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Quadrilaterals
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon