Question

Show that "the range of the first seven multiples of the smallest odd prime number is also a multiple of that prime number . "

Answer 1

$\Rightarrow$ The smallest odd prime is $3$.

$\Rightarrow$ The first seven multiple of $3=3,6,9,12,15,18,21$.

$\Rightarrow$ Here, the highest number is $21$ and lowest number is $3$.

$\Rightarrow$ The range of this multiples = Highest number - lowest number

$\Rightarrow$ The range of this multiples $=21-3=18$

$\Rightarrow$ We know that $18$ is divisible by $3$.

Hence, we proved that, "the range of the first seven multiples of the smallest odd prime number is also a multiple of that prime number . "