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Question

Show that the square of an odd positive integer is of the form 8q + 1, for some integer q.

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Solution

To Prove: that the square of an odd positive integer is of the form 8q + 1, for some integer q.

Proof: Since any positive integer n is of the form 4m + 1 and 4m + 3

If n = 4m + 1

If n = 4m + 3

Hence n2 integer is of the form 8q + 1, for some integer q.


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