Question

Show that the straight line $3x+2y-12=0$ and $6x+4y+8=0$ are parallel.

Answer 1

Slope of the straight line $3x+2y-12=0$ is $m_1=-\frac{coefficientofx}{coefficientofy}=-\frac{3}{2}$
Similarly, the slope of the line $6x+4y+8=0$ is $m_2=-\frac{6}{4}=-\frac{3}{2}$
$\therefore$ $m_1=m_2$. Hence, the two straight lines are parallel.