Line 1:- l1=1213,m1=−313,n1=−413
Line 2:- l2=413,m2=1213,n2=313
l1l2+m1m2+n1n2=(1213×413)+(−313×1213)+(−413×313)
=48169+−36169+−12169=48−48169
=0
∴l1l2+m1m2+n1n2=0
∴ Given Lines are perpendicular
Line 2:- l2=413,m2=1213,n2=313
Line 3:- l3=313,m3=−413,n3=1213
l3l2+m3m2+n3n2=(413×313)+(1213×−413)+(313×1213)
=12169+−48169+36169=48−48169=0
∴l3l2+m3m2+n3n2=0
∴ Two lines are perpendicular
Line 3:- l3=313,m3=−413,n3=1213
Line 1:- l1=1213,m1=−313,n1=−413
l1l3+m1m3+n1n3=(313×1213)+(−413×313)+(1213×−413)
=36169+12169+−48169=48−48169=0
∴l1l3+m1m3+n1n3=0
∴ Two lines are perpendicular
Hence given three Lines are mutually perpendicular.