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Question

Show that the three lines with direction cosines
1213313,413;413,1213,313;313,413,1213 are mutually perpendicular.

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Solution

Line 1:- l1=1213,m1=313,n1=413
Line 2:- l2=413,m2=1213,n2=313
l1l2+m1m2+n1n2=(1213×413)+(313×1213)+(413×313)
=48169+36169+12169=4848169
=0
l1l2+m1m2+n1n2=0
Given Lines are perpendicular
Line 2:- l2=413,m2=1213,n2=313
Line 3:- l3=313,m3=413,n3=1213
l3l2+m3m2+n3n2=(413×313)+(1213×413)+(313×1213)
=12169+48169+36169=4848169=0
l3l2+m3m2+n3n2=0
Two lines are perpendicular
Line 3:- l3=313,m3=413,n3=1213
Line 1:- l1=1213,m1=313,n1=413
l1l3+m1m3+n1n3=(313×1213)+(413×313)+(1213×413)
=36169+12169+48169=4848169=0
l1l3+m1m3+n1n3=0
Two lines are perpendicular
Hence given three Lines are mutually perpendicular.


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