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Question

Show that the vector is parallel to a vector A=^i^j+2^k is parallel to a vector B=3^i3^j+6^k.

A
13 times the magnitude of B.
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B
14 times the magnitude of B.
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C
12 times the magnitude of B.
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D
None of these
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Solution

The correct option is A 13 times the magnitude of B.
A vector A is parallel to an another vector B if it can be written as
A=mB where m is a constant.
Here, A=(^i^j+2^k)=13(3^i3^j+6^k)
or A=13B
This implies that A||B and magnitude of A is 13 times the magnitude of B.

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