Show that the vector is parallel to a vector →A=^i−^j+2^k is parallel to a vector →B=3^i−3^j+6^k.
A
13 times the magnitude of →B.
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B
14 times the magnitude of →B.
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C
12 times the magnitude of →B.
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D
None of these
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Solution
The correct option is A13 times the magnitude of →B. A vector →A is parallel to an another vector →B if it can be written as →A=m→B where m is a constant. Here, →A=(^i−^j+2^k)=13(3^i−3^j+6^k) or →A=13→B This implies that →A||→B and magnitude of →A is 13 times the magnitude of →B.