wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Show that the vector is parallel to a vector A=^i^j+2^k is parallel to a vector B=3^i3^j+6^k.

A
13 times the magnitude of B.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
14 times the magnitude of B.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12 times the magnitude of B.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 13 times the magnitude of B.
A vector A is parallel to an another vector B if it can be written as
A=mB where m is a constant.
Here, A=(^i^j+2^k)=13(3^i3^j+6^k)
or A=13B
This implies that A||B and magnitude of A is 13 times the magnitude of B.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Operations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon