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Sub-Atomic Particles

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show that the wavelenght of electromagnetic radiation is equal to de broglie wavelengh. of photon

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Q. Show that the wavelength of electromagnetic radiation is equal to the de Broglie wavelength of its quantum (photon).

Q. The energy of a photo is equal to the kinetic energy of proton. Let

λ_{1}

be the de-Broglie wavelength of the photon and

λ_{2}

be the wavelength of the radiation and the de-Broglie wavelength of a photon of that radiation?

Q. If the wavelength of electromagnetic radiation is doubled, what happens to the energy of photon?

Q. The electron with The electron with de Broglie wavelength

λ

is bombarded on a metal target. Found that photons are emitted through de Broglie wavelength.

Q. If we assume that penetrating power of any radiation/particle is inversely proportional to the De-broglie wavelength of the particle, then

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