Show that there is no value of n for which -2n nbsp- times- 5n- ends in 5-

We can write:(2n nbsp; times; 5n) = (2 nbsp; times; 5)n nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; = 10nFor any value of n, we get 0 ...

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Range, Domain and Codomain

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Question

Show that there is no value of n for which (2ⁿ × 5ⁿ) ends in 5.

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Show that there is no value of n for which ( $2^{n} \times 5^{n}$ ) ends in 5.

n

2 n + 8 : 5 n - 3,

n^{th}

1, 3, 7

9

\frac{2^{n}}{5^{n}}

2, 4, 6

8

\frac{4^{n} - 2^{n}}{5^{n}}

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\frac{5^{n} - 4 n}{10^{n}}

0

\frac{10^{n} - 8^{n} - 5^{n} + 4^{n}}{10^{n}}

(t_{n}), S_{n} = 2 n^{2} + 5 n,

t_{n}

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