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Question

Show that ABC, where A(2,0),B(2,0),C(0,2) and PQR where P(4,0),Q(4,0),R(0,4) are similar triangles.

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Solution

Given A(2,0);B(2,0);C(0,2) & P(4,0);Q(4,0);R(0,4)
AB=42+0=4PQ=(8)2+0=8
BC=4+4=22QR=42+42=42
AC=22+22=22PR=(4)2+(4)2=42
ABPQ=BCQR=ACPR=12
ΔABCΔPQR (SSS cong)

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