Show that $x = 1$ , $y = 3$ satisfy the linear equation $3 x - 4 y + 9 = 0$

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Solution

satisfying (1,3) in 3x-4y+9=0
$\Rightarrow 3 \times 1 - 4 \times 3 + 9 = 0$
$\Rightarrow 3 - 12 + 9 = 0$
$\Rightarrow 12 - 12 = 0$ $\Rightarrow 0 = 0$
$∴$ LHS=RHS.
Hence proved.

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