Show with balanced equations what happens when the following are mixed:

Aqueous solution of potassium chromate and acid.

2 C r O_{4}^{2 -} + 2 H^{+} ⇌ {C r}_{2} O_{7}^{2 -} + H_{2} O

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2 C r O_{4}^{2 -} + 10 H^{+} ⇌ {C r}_{2} O_{3}^{2 -} + 5 H_{2} O

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2 C r O_{4}^{2 -} + 6 H^{+} ⇌ {C r}_{2} O_{5}^{2 -} + 3 H_{2} O

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None of these

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Solution

The correct option is C $2 C r O_{4}^{2 -} + 2 H^{+} ⇌ {C r}_{2} O_{7}^{2 -} + H_{2} O$ .
Yellow-colored chromate changes to orange colored dichromate but chromium stays in +6 oxidation in both the compounds.
$2 C r O_{4}^{2 -} + 2 H^{+} \to {C r}_{2} O_{7}^{2 -} + H_{2} O$

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Similar questions

{C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O

Z n + C u S O_{4} ⟶ Z n S O_{4} + C u

2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O

2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

{C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O

Z n + C u S O_{4} ⟶ Z n S O_{4} + C u

2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O

2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

U O_{2} + {C r}_{2} O_{7}^{2 -} ⟶ U O_{2}^{2 +} + {C r}^{2 +} + H_{2} O

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

2 C r O_{4}^{2 -} + 2 H^{+} \to C r_{2} O_{7}^{2 -} + H_{2} O

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