Show with the help of diagrams how you would connect three resistors each of resistance 6 - so that the combination has a resistance of i 9 - ii 4-

(i) Equivalent resistance = 9 Ω R_eq = 6 + (6 || 6) = 6 + 6 × 6/ 6 + 6 = 6 + 3 = 9 Ω (ii) Equivalent resistance = 4 Ω R_eq = (6+6) || 6 = 12 || 6 = 12 × ...

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Standard X

Physics

Equivalent Resistance of a System of Resistor

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Question

Show with the help of diagrams how you would connect three resistors each of resistance $6 Ω$ so that the combination has a resistance of (i) $9 Ω$ (ii) $4 Ω$

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Solution

(i) Equivalent resistance = $9 Ω$

$R_{e q} = 6 + (6 | | 6) = 6 + \frac{6 \times 6}{6 + 6} = 6 + 3 = 9 Ω$

(ii) Equivalent resistance = $4 Ω$

$R_{e q} = (6 + 6) | | 6 = 12 | | 6 = \frac{12 \times 6}{12 + 6} = 4 Ω$

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Q. Question 11 (ii)
Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of

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Q. Question 11 (ii)
Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of

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Show with the help of diagrams how you would connect three resistors each of resistance 6 Ω so that the combination has a resistance of (i) 9 Ω (ii) 4 Ω

(i) Equivalent resistance = 9 Ω Req=6+(6||6)=6+6×66+6=6+3=9 Ω (ii) Equivalent resistance = 4 Ω Req=(6+6)||6=12||6=12×612+6=4 Ω

Show with the help of diagrams how you would connect three resistors each of resistance $6 Ω$ so that the combination has a resistance of (i) $9 Ω$ (ii) $4 Ω$

(i) Equivalent resistance = $9 Ω$

$R_{e q} = 6 + (6 | | 6) = 6 + \frac{6 \times 6}{6 + 6} = 6 + 3 = 9 Ω$

(ii) Equivalent resistance = $4 Ω$

$R_{e q} = (6 + 6) | | 6 = 12 | | 6 = \frac{12 \times 6}{12 + 6} = 4 Ω$