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Question

Shown above is a distribution of charges. The flux of electric field due to these charges through the surface S is :
431015_c491ff7f59ee4bc3b3f583916a11316b.png

A
3q/ε0
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B
2q/ε0
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C
q/ε0
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D
zero
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Solution

The correct option is D zero
Total charge enclosed by surface S is Qen=+qq=0
Applying Gauss's law , the electric flux through S is ϕ=Qenϵ0=0

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