Shown above is the figure of a playground. Find the area of the playground.

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Solution

The given playground is a trapezium, And area of trapezium is $= \frac{1}{2} \times (s u m o f p a r r a l l e l s i d e s) \times h e i g h t$
Therefore, area of playground $= \frac{1}{2} (b + a) \times h$

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Shown above is the figure of a playground. Find the area of the playground.

The given playground is a trapezium, And area of trapezium is =12×(sumofparrallelsides)×heightTherefore, area of playground =12(b+a)×h

The given playground is a trapezium, And area of trapezium is $= \frac{1}{2} \times (s u m o f p a r r a l l e l s i d e s) \times h e i g h t$
Therefore, area of playground $= \frac{1}{2} (b + a) \times h$