Shown in the figure is a circular loop of radius r and resistance R. A variable magnetic field of induction B=B0e−t is established inside the coil. If the key (K) is closed, the electrical power developed right after closing the switch is equal to
A
B20πr2R
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B
B010r3R
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C
B20π2r4R5
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D
B20π2r4R
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Solution
The correct option is DB20π2r4R P=e2R;e=−ddt(BA)=Addt(B0e−t)=AB0e−t ⇒P=1R(AB0e−t)2=A2B20e−2tR At the time of starting t = 0 so P=A2B20R ⇒P=(πr2)2B20R=B20π2r4R