CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

shows a circular wire-loop of radius a, carrying a current i, placed in a perpendicular magnetic field B. (a) Consider a small part dl of the wire. Find the force on this part of the wire exerted by the magnetic field. (b) Find the force of compression in the wire.
1077217_769e3e1749774bf7b4dae18569e23bb5.png

Open in App
Solution

(a) Fdl=i×dl×B towards centre. (By cross product rule)
(b) Let the length of subtends an small angle of 2θ at the centre
Here,
2Tsinθ=i×dl×B
2Tθ=i×a×2θ×B [As θ0,sinθ0]
T=i×a×B
T=a i B
Force of compression on the wire =iaB








1044806_1077217_ans_5b342b3b40524acb9734e6757eedca02.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Magnetic Field Due to a Current Carrying Wire
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon