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Standard VII

Mathematics

Perimeter of Square and Rectangle

Shriya walked...

Question

Shriya walked $70$ m to the east from point $A,$ then turned right and walked $30$ m. At last, she turned right and went for $30$ m and reached point $B .$ Then the distance between $A$ and $B$ is

170

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Solution

The correct option is B $50$ m

In right triangle $A E B,$
$A B = \sqrt{A E^{2} + E B^{2}} = \sqrt{30^{2} + 40^{2}}$
$\Rightarrow A B = 50$ m

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Shriya walked 70 m to the east from point A, then turned right and walked 30 m. At last, she turned right and went for 30 m and reached point B. Then the distance between A and B is

The correct option is B 50 m In right triangle AEB, AB=√AE2+EB2=√302+402 ⇒AB=50 m

Shriya walked $70$ m to the east from point $A,$ then turned right and walked $30$ m. At last, she turned right and went for $30$ m and reached point $B .$ Then the distance between $A$ and $B$ is

The correct option is B $50$ m

In right triangle $A E B,$
$A B = \sqrt{A E^{2} + E B^{2}} = \sqrt{30^{2} + 40^{2}}$
$\Rightarrow A B = 50$ m