Question

$Si\left(s\right)+2C{l}_2\left(g\right)\to SiC{l}_4\left(l\right)$
In one reaction, 0.507 mole of $SiC{l}_4$ is produced how many moles of molecular chlorine were used in the reaction?

• A. 1.023
• B. 1.014
• C. 2.064
• D. 1.025

Answer 1

The correct option is B 1.014

$Si\left(s\right)+2C{l}_2\left(g\right)\to SiC{l}_4\left(l\right)$
Two moles of chlorine is required for one mole of $SiC{l}_4$.
So for 0.507 mole of $SiC{l}_4$, $2\times 0.507=1.014$ moles of chlorine is required.