SI unit of gravitational constant is:

N^{2} m^{2} k g^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N m k g^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N^{2} m k g^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N m^{2} k g^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $N m^{2} k g^{- 2}$
gravitational force $F$
$F = \frac{G M_{1} m_{2}}{R^{2}}$
unit of $F = N$
unit of mass = $K g$
unit of $R = m$
unit of $G = N m^{2} K g^{- 2}$

Suggest Corrections

Similar questions

SI unit of gravitational constant is

N m^{2} k g^{- 2}

G = 6.67 \times 10^{- 11} N - m^{2} / k g^{2}

S I

Join BYJU'S Learning Program