SI unit of permittivity - is- if Coulomb C- Meter m and Force N are fundamental Quantities

The correct option is C C2m 2 N 1F=14πϵq_1q_2r^2⇒ϵ = 14πq_1q_2Fr^2 =C^2 m^ 2N^ 1 ...

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Standard VIII

Mathematics

Physical Quantities

SI unit of pe...

Question

SI unit of permittivity $(ϵ)$ is….. (if Coulomb (C), Meter (m) and Force (N) are fundamental Quantities

C²m^-3 N^-1

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C^-1m² N^-2

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C²m² N²

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C²m^-2 N^-1

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Solution

The correct option is D C²m^-2 N^-1
F= $\frac{1}{4 π ϵ} \frac{q_{1} q_{2}}{r^{2}} \Rightarrow ϵ = \frac{1}{4 π} \frac{q_{1} q_{2}}{F r^{2}} = C^{2} m^{- 2} N^{- 1}$

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SI unit of permittivity (ϵ) is….. (if Coulomb (C), Meter (m) and Force (N) are fundamental Quantities

The correct option is D C2m-2 N-1F=14πϵq1q2r2⇒ϵ=14πq1q2Fr2=C2m−2N−1

SI unit of permittivity $(ϵ)$ is….. (if Coulomb (C), Meter (m) and Force (N) are fundamental Quantities

The correct option is D C²m^-2 N^-1
F= $\frac{1}{4 π ϵ} \frac{q_{1} q_{2}}{r^{2}} \Rightarrow ϵ = \frac{1}{4 π} \frac{q_{1} q_{2}}{F r^{2}} = C^{2} m^{- 2} N^{- 1}$