SI unit of permittivity of free space is:

Farad

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Weber

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C^{2} N^{- 1} m^{- 2}

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C^{2} N^{- 1} m^{- 1}

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Solution

The correct option is D $C^{2} N^{- 1} m^{- 2}$
Coulombic force between two charges is given by
F=1/4π€ (q'.q″/r²)
From here, the SI UNIT of permittivity comes out is
= coulomb²/Newton-meter²
C²/N-m²

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(c)

(μ_{0})

(ϵ_{0})

c = \frac{1}{\sqrt{μ_{0} ϵ_{0}}}

ϵ_{0}

N^{- 1} C^{2} m^{- 2}

μ_{0}

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