Sides of a triangle ABC are in AP- then cosA is equal toA- 3 c-4 b-2 bB- 3 c-4 b-2 cC- 4 c-3 b-2 bD- 4 c-3 b-2 c

The correct option is D Sides are in AP nbsp;2b=a+c cos A= b^2+c^2 a^2/2bc=b^2+c^2 (2b c)^2/2bc=4bc 3b^2/2bc=4c 3b/2c ...

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Sum of n Terms

Sides of a tr...

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Sides of a triangle ABC are in AP, then cosA is equal to

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¯ ¯ ¯ a - 2 ¯ ¯ b + 3 ¯ ¯ c,

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