Question

Sides of a triangle are in the ratio $12:17:25$ and its perimeter is $540cm$. Find its area.

Answer 1

Given $\Rightarrow$ $a:b:c=12:17:25$

Let, $a=12k,b=17k,c=25k$

$a+b+c=540$

$12k+17k+25k=540$

$54k=540$

$k=10$

so $a=120,b=170,$$c=250$

$s=\frac{a+b+c}{2}=\frac{540}{2}$

$s=270$

$Area=\sqrt{s(s-a)(s-b)(s-c)}$

$△$$\sqrt{270(270-120)(270-170)(270-250)}$

$△=9000c{m}^2$