Question

Sides of two similar triangles are in the ratio $4:9.$ Areas of these triangles are in the ratio:

• A. $2:3$
• B. $4:9$
• C. $81:16$
• D. $16:81$

Answer 1

The correct option is D $16:81$

Since,
$△ABC$ $\sim$ $△PQR$

Also, The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

$\therefore$ $\frac{A\left(△ABC\right)}{A(△PQR}$ $=\frac{4^2}{9^2}$ $=\frac{16}{81}$.