∑n=0∞n2+4n! is equal to
6e
5e
4e
None of these
Explanation for the correct answer:
Simplifying the given expression:
⇒∑n=0∞n2+4n!⇒∑n=0∞n2n!+∑n=0∞4n!⇒∑n=0∞1(n-2)!+1(n-1)!+∑n=0∞4n!⇒e+e+4e∵e=1+11!+12!+13!+….⇒6e
Thus, ∑n=0∞n2+4n!=6e
Therefore, the correct answer is option (A).