$σ s p^{2} - s$ bond is present in:

C H_{4}

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N H_{3}

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S i C l_{4}

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C H_{2} = C H C l

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Solution

The correct option is D $C H_{2} = C H C l$
In option D, carbon is $s p^{2}$ hybridised because of the presence of double bond and the attached hydrogen has s orbital overlapping.

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$C H_{2}$	$N H_{3}$

N H_{3}

C H_{4}

How many covalent bonds are present in the following compounds?

(i) $C O_{2}$

(ii) $H_{2} O$

(iii) $C H_{4}$

(iv) $N_{2}$

(v) $N H_{3}$

C H_{4}, N H_{3} a n d H_{2} O

C H_{4}

(C H_{4})

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