The correct option is A 0.25σz
Under the point load, the vertical stress is given by
σz=0.4775Qz2
(From Boussinesq's equation at r/z =0)
∴σ2z=0.4775Q4z2=0.25σz
The depth at which σz=0.1 per unit area is z=√4.775=2.185 units under the load.
Thus isobar extends up to 2.185 units of depth under the load to dissipate 90% of stresses.