Silver Chloride dissolves in excess ammonia due to the formation of a soluble complex whose formula is ?

[A g (N H_{3}] C l

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[A g (N H_{3})_{2}] C l

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[A g (N H_{3})_{3}] C l

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[A g (N H_{3})_{4}] C l

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Solution

The correct option is C $[A g (N H_{3})_{2}] C l$
$C l^{-}$ reacts with $A g^{+}$ to form soluble AgCl. The formula of the compoound is $[A g (N H_{3})_{2}] C l$ .

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Similar questions

AgCl reacts with ammonia to form water soluble

[A g (N H_{3})_{2}] C l

Q. Calculate the number of formula units of

[A g (N H_{3})_{2}] C l

in 1 kilomole of

[A g (N H_{3})_{2}] C l

Q. Write IUPAC names of the following complexes.

[P t (N H_{3})_{2} C l_{2}]

[A g (N H_{3})_{2}] C l

[C r (H_{2} O)_{4} C l_{2}] C l

A metal M forms a volatile chloride containing 65.5% chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride.

[M = 56, Cl = 35.5]

Given: Cl = 65.5%

M = (100-65.5)% = 34.5 %

H g {C l}_{2}

is a covalent compound, sparingly soluble in water, the solubility increases by the addition of chloride ions due to:

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Silver Chloride dissolves in excess ammonia due to the formation of a soluble complex whose formula is ?

The correct option is C [Ag(NH3)2]ClCl− reacts with Ag+ to form soluble AgCl. The formula of the compoound is [Ag(NH3)2]Cl.

The correct option is C $[A g (N H_{3})_{2}] C l$
$C l^{-}$ reacts with $A g^{+}$ to form soluble AgCl. The formula of the compoound is $[A g (N H_{3})_{2}] C l$ .